7-[4+2(a-3)]=11(a+2)

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Solution for 7-[4+2(a-3)]=11(a+2) equation:


Simplifying
7 + -1[4 + 2(a + -3)] = 11(a + 2)

Reorder the terms:
7 + -1[4 + 2(-3 + a)] = 11(a + 2)
7 + -1[4 + (-3 * 2 + a * 2)] = 11(a + 2)
7 + -1[4 + (-6 + 2a)] = 11(a + 2)

Combine like terms: 4 + -6 = -2
7 + -1[-2 + 2a] = 11(a + 2)
7 + [-2 * -1 + 2a * -1] = 11(a + 2)
7 + [2 + -2a] = 11(a + 2)

Combine like terms: 7 + 2 = 9
9 + -2a = 11(a + 2)

Reorder the terms:
9 + -2a = 11(2 + a)
9 + -2a = (2 * 11 + a * 11)
9 + -2a = (22 + 11a)

Solving
9 + -2a = 22 + 11a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-11a' to each side of the equation.
9 + -2a + -11a = 22 + 11a + -11a

Combine like terms: -2a + -11a = -13a
9 + -13a = 22 + 11a + -11a

Combine like terms: 11a + -11a = 0
9 + -13a = 22 + 0
9 + -13a = 22

Add '-9' to each side of the equation.
9 + -9 + -13a = 22 + -9

Combine like terms: 9 + -9 = 0
0 + -13a = 22 + -9
-13a = 22 + -9

Combine like terms: 22 + -9 = 13
-13a = 13

Divide each side by '-13'.
a = -1

Simplifying
a = -1

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